int array[]={1,2,3,4,5,6,7,8}; #define SIZE (sizeof(array)/sizeof(int)) main()

int array[]={1,2,3,4,5,6,7,8};
#define SIZE (sizeof(array)/sizeof(int))
main()
{
if(-1<=SIZE) printf("1");
else printf("2");
}

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int array[]={1,2,3,4,5,6,7,8}; #define SIZE (sizeof(array)/sizeof(int)) main() { if(-1<=SIZE)..

Answer / c.p.senthil

program prints "2"

Here sizeof returns unsigned int value
so sizeof(array)/sizeof(int)
=> 32(unsigned int)/4(unsigned int)
=> 8 (unsigned int value)

During comparison, the datatypes are different on both sides of if condition
-1(signed int) <= 8(unsigned int)

so by rule of type conversion in c,
signed int gets converted to unsigned int

hence expression becomes
0xFFFFFFFF(unsigned int equivalent of -1) <= 8(unsigned int)

Hence overall condition becomes FALSE

Is This Answer Correct ?

72 Yes

6 No

int array[]={1,2,3,4,5,6,7,8}; #define SIZE (sizeof(array)/sizeof(int)) main() { if(-1<=SIZE)..

Answer / dnyaneshwar

Is This Answer Correct ?

3 Yes

15 No

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