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52.write a “Hello World” program in “c” without using a
semicolon?
53.Give a method to count the number of ones in a 32 bit number?
54.write a program that print itself even if the source file
is deleted?
55.Given an unsigned integer, find if the number is power of 2?
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Answer / tyutyjtytydf
#include<stdio.h>
#include<conio.h>
main()
{
if(puts("hello world"))
{}
}
| Is This Answer Correct ? | 10 Yes | 0 No |
Answer / sainath
A small correction in the above answer. Use if condition as
shown below.
#include<stdio.h>
void main()
{
if(printf(%s, "Hello World"))
{
}
}
Answer for the last ques. i.e no. 55
unsigned int x;
if(x < 0) //Error checking only. Unsigned int shudn't
//have a negative value
return 0;
else
return !(x $ (x-1));
The logic here is, if we do bitwise 'and' with two
consecutive numbers, the greater of which is a power of 2
then the answer is 0.
Eg. 8 - 1000
8-1 - 0111
and & - 0000
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / ss
#include<stdio.h>
void main(){
if(printf("Hello World"))
{
}
}
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / amogh
53.
'num' is 32 bit integer
count=0;
for(;num!=0;count++)
num&=num-1;
55.
if(num&(num -1) == 0)
printf("%d is power of 2",num);
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / hussain reddy
/* mypro.c*/
#include<stdio.h>
void main()
{
remove("mypro.c");
}
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / lokesh n. jaliminche
/*program to check if number is power of 2
#include <stdio.h>
unsigned int check_power(unsigned int value)
{
unsigned int count = 0;
while (value > 0) {
if ((value & 1) == 1)
count++;
value >>= 1;
}
return count;
}
int main()
{
unsigned int n, count;
printf("Enter the number \n");
scanf("%d",&n);
count=check_power(n);
if(count == 1)
{
printf("number is power of 2\n");
}
else
{
printf("number is not power of 2\n");
}
printf("set bits == %d",count);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / lokesh n. jaliminche
#include <stdio.h>
unsigned int check_power(unsigned int value)
{
unsigned int count = 0;
while (value > 0) {
if ((value & 1) == 1)
count++;
value >>= 1;
}
return count;
}
int main()
{
unsigned int n, count;
printf("Enter the number \n");
scanf("%d",&n);
count=check_power(n);
if(count == 1)
{
printf("number is power of 2\n");
}
else
{
printf("number is not power of 2\n");
}
printf("set bits == %d",count);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sankar kiran
#include<stdio.h>
#include<conio.h>
void main()
{
while(printf("Hello World"))
{
break;
}
getch();
}
| Is This Answer Correct ? | 6 Yes | 8 No |
Answer / swastisundar bose
52.
#include<stdio.h>
void main(){
if("Hello World")
{
}
}
| Is This Answer Correct ? | 17 Yes | 20 No |
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C 
