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A seller has a set of apples out of which he sells one
half of it and half an apple to his first customer.then he
sells half of the remaining apples and a half apple to his
second customer.Then he sells half of the remaining apple
and ? apple to his third customer and so on.This repeats
upto 7th customer and no more apples are remaining . Find
the total no of apples he had.
- 8 Answers
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Answer / lava kumar
I think U r wrong Tina,because
according to u,
1st customer=43 apples
2nd customer=21.5 apples
An apple cannot be cut
I think the answer is 127 check it out...
| Is This Answer Correct ? | 37 Yes | 7 No |
Answer / viki
Sold. Remaining
X/2 +1/2. x/2-1/2
X/4-1/4+1/2 x/4-1/4-1/2=x/4-3/4
Proceed like this up to 7 the term and equate last term equal to zero
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / suganya
i didnt understand can any one explain again with a clear explanation pls
| Is This Answer Correct ? | 1 Yes | 3 No |
Answer / sreenath
Answer is 67.
If half of the apple is cut every time nd forr 7th time he left wth empty hands means.7th time he sold half apple nd remainig half he gave it for free.so for 7th one he has 1 apple then at first he have 64 nd inclusing with dat half pieces he gave to customers the answer is 67.
| Is This Answer Correct ? | 1 Yes | 13 No |
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