Consider the following code fragment: int main(void) { int m = 4;

Consider the following code fragment:
int main(void) {
int m = 4;
mystery ( m );
mystery ( m );
printf("%d", m);
return 0;
}

What is the output on the monitor if mystery is defined as
follows ?

void mystery (int m) {
m = m+3;
}

Question Posted / guest

2 Answers
4729 Views
CDAC, Wipro, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

Consider the following code fragment: int main(void) { int m = 4; mystery ( m ); ..

Answer / c++ coder

Output will be 4 only.

since the argument is not passed by reference so a local
copy of m is used in the function call which is local to
mystery() it will not have any impact on the variable m
which is used in main() function.

Is This Answer Correct ?

6 Yes

1 No

Consider the following code fragment: int main(void) { int m = 4; mystery ( m ); ..

Answer / rahul darekar

since in c lang we have to define fun first before we use it
but in this program fun mystery() in not defined and still
it is called so it will give error.

Is This Answer Correct ?

3 Yes

1 No

Post New Answer

More C++ General Interview Questions

What is the full form of india?

0 Answers

What is the output of: String a1 = "Hello"; String a2 = "world!"; String* s1 = &a2; String& s2 = a1; s1 = &a1; s2 = a2; std::cout << *s1 << " " << s2 << std::endl;

4 Answers Lehman Brothers,

What is a sequence in c++?

0 Answers

Explain pass by value and pass by reference.

0 Answers

What are the uses of pointers?

0 Answers

What's the order in which the objects in an array are destructed?

0 Answers

Write a program for Divide a number with 2 and Print the output ( NOTE: Check for divide by zero error).

0 Answers

what is multi-threading in C++?