how does the below eqation proceed to be solved:
x*=y+z

options: x=x*y+z or x=x*(y+z)



how does the below eqation proceed to be solved: x*=y+z options: x=x*y+z or x=x*(y+z) ..

Answer / ramakrishnan

x=x*(y+z)

Is This Answer Correct ?    7 Yes 0 No

Post New Answer

More C Sharp Code Interview Questions

How to export 2 datatables of a single dataset to 2 different worksheets of a single MSExcel file ?

0 Answers   Eastcom Systems,


How to add a value from textBox over an existing certain column in SQL Server

0 Answers  


Code for Searching for Multiple Matches with the MatchCollection Class?

0 Answers   TCS,


Write a program to count 3Letter, 4Letter and 5Letter words from a file and print the number of 3Letter, 4Letter and 5Letter words. Delimiter is space, tab, hifen. Also we should not consider the line in the file after we encounter # in that line.

0 Answers   Mind Tree,


Event Handling in C# Triggering a Button

1 Answers  






Can you declare an array of mixed Types?

1 Answers   HCL,


IS Array list is generic or non generic

1 Answers  


program to reverse the order of digits in a given number of any length.

1 Answers   Mind Tree,


how do i copy textbox contents of 1 form to another form

4 Answers   Wipro,


Coding for using Nullable Types in C#?

1 Answers  


c# coding for a program that takes a 3 digit number n and finds out whether the number 2^n + 1 is prime, or if it is not prime find out its factors not using the Big-integer and Exponential Function's.

1 Answers   TCS,


how does the below eqation proceed to be solved: x*=y+z options: x=x*y+z or x=x*(y+z)

1 Answers  


Categories
  • ASP.NET Code Interview Questions ASP.NET Code (46)
  • VB.NET Code Interview Questions VB.NET Code (9)
  • C Sharp Code Interview Questions C Sharp Code (51)
  • ADO.NET Code Interview Questions ADO.NET Code (8)