Answer / asadhsheriff

int main()
{
int a[20],i,j,count=0;
memset(a,0,20);
for(;count<=20;)
{
scanf("%d",&j);
if(a[j]==0)
{
count++;
a[j]=j;
}
}
i=20(10)/2;
printf("The sum is %d",i);
}

Answer / douglas

I so far have nothing

Answer / kaiss

we will use looping for making this program.

Answer / sanjay bhosale

/ Duplicate.cpp : main project file.
// Program : To find duplicate no in array by traversing it only once.
#include "stdafx.h"
#include<stdio.h>
#include<malloc.h>

using namespace System;

int main(array<System::String ^> ^args)
{
int *arr;
int val = 0;
int size = 0;
printf(" \n Enter the no of elements in array :");
scanf_s("%d",&size);
arr = (int *)malloc(sizeof(int)*size);
printf("\n Enter elements in the range 1 to %d:",size);
for(int i=0;i<size;i++)
{
scanf_s("%d",&val);
if(val<1 && val>=size)
{
printf("\n enter element again :\t");
i--;
}
else
*(arr+i) = val;
}
int sum = 0;
getchar();
printf("Array is :\n");
for(int i=0;i<size;i++)
{
printf("\t %d",arr[i]);
sum+= arr[i];
}
getchar();
printf("\n sum : %d",sum);
int diff = sum-(size*(size-1)/2.0);
printf(" Duplicate element is :%d\n",diff);
getchar();
return 0;
}


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