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Ca some one please help me with aC code to allow user enter
numbers from 1 to 20 without repeating and prnt the sum of
those numbers
thnx

Answers were Sorted based on User's Feedback



Ca some one please help me with aC code to allow user enter numbers from 1 to 20 without repeating ..

Answer / asadhsheriff

int main()
{
int a[20],i,j,count=0;
memset(a,0,20);
for(;count<=20;)
{
scanf("%d",&j);
if(a[j]==0)
{
count++;
a[j]=j;
}
}
i=20(10)/2;
printf("The sum is %d",i);
}

Is This Answer Correct ?    1 Yes 0 No

Ca some one please help me with aC code to allow user enter numbers from 1 to 20 without repeating ..

Answer / douglas

I so far have nothing

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Ca some one please help me with aC code to allow user enter numbers from 1 to 20 without repeating ..

Answer / kaiss

we will use looping for making this program.

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Ca some one please help me with aC code to allow user enter numbers from 1 to 20 without repeating ..

Answer / sanjay bhosale

/ Duplicate.cpp : main project file.
// Program : To find duplicate no in array by traversing it only once.
#include "stdafx.h"
#include<stdio.h>
#include<malloc.h>

using namespace System;

int main(array<System::String ^> ^args)
{
int *arr;
int val = 0;
int size = 0;
printf(" \n Enter the no of elements in array :");
scanf_s("%d",&size);
arr = (int *)malloc(sizeof(int)*size);
printf("\n Enter elements in the range 1 to %d:",size);
for(int i=0;i<size;i++)
{
scanf_s("%d",&val);
if(val<1 && val>=size)
{
printf("\n enter element again :\t");
i--;
}
else
*(arr+i) = val;
}
int sum = 0;
getchar();
printf("Array is :\n");
for(int i=0;i<size;i++)
{
printf("\t %d",arr[i]);
sum+= arr[i];
}
getchar();
printf("\n sum : %d",sum);
int diff = sum-(size*(size-1)/2.0);
printf(" Duplicate element is :%d\n",diff);
getchar();
return 0;
}


Might this help you........

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