Answer / chauhan rakesh botad

#include<stdio.h>

int main()
{
int a[100], i;
printf("To pop enter -1\n");
for(i = 0;;)
{
printf("Push ");
scanf("%d", &a[i]);
if(a[i] == -1)
{
if(i == 0)
{
printf("Underflow\n");
}
else
{
printf("pop = %d\n", a[--i]);
}
}
else
{
i++;
}
}
}
{
programmer : clx321
file : stack.pas
unit : Pstack.tpu
}
program TestStack;
{this program uses ADT of Stack, I will assume that the unit
of ADT of Stack has already existed}

uses
PStack; {ADT of STACK}

{dictionary}
const
mark = '.';

var
data : stack;
f : text;
cc : char;
ccInt, cc1, cc2 : integer;

{functions}
IsOperand (cc : char) : boolean; {JUST Prototype}
{return TRUE if cc is operand}
ChrToInt (cc : char) : integer; {JUST Prototype}
{change char to integer}
Operator (cc1, cc2 : integer) : integer; {JUST Prototype}
{operate two operands}

{algorithms}
begin
assign (f, cc);
reset (f);
read (f, cc); {first elmt}
if (cc = mark) then
begin
writeln ('empty archives !');
end
else
begin
repeat
if (IsOperand (cc)) then
begin
ccInt := ChrToInt (cc);
push (ccInt, data);
end
else
begin
pop (cc1, data);
pop (cc2, data);
push (data, Operator (cc2, cc1));
end;
read (f, cc); {next elmt}
until (cc = mark);
end;
close (f);
end
}

how to generate sparse matrix in c

3 Answers  

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You have an int array with n elements and a structure with three int members. ie struct No { unsigned int no1; unsigned int no2; unsigned int no3; }; Point1.Lets say 1 byte in the array element is represented like this - 1st 3 bits from LSB is one number, next 2 bits are 2nd no and last 3 bits are 3rd no. Now write a function, struct No* ExtractNos(unsigned int *, int count) which extracts each byte from array and converts LSByte in the order mentioned in point1.and save it the structure no1, no2, no3. in the function struct No* ExtractNos(unsigned int *, int count), first parameter points to the base address of array and second parameter says the no of elements in the array. For example: if your array LSB is Hex F7 then result no1 = 7, no2 = 2, no3 = 7. In the same way convert all the elements from the array and save the result in array of structure.

2 Answers   Qualcomm,

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main() { static char *s[]={"black","white","yellow","voilet"}; char **ptr[]={s+3,s+2,s+1,s}, ***p; p=ptr; **++p; printf("%s",*--*++p+3); }

1 Answers  

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