Answer / sanjay bhosale

#include<stdio.h>
int main()
{
int x=0,y=-3;
printf("\n Enter the number :\t");
scanf("%d",&x);
int xor, and, temp,tempvar=x;
x = (x>0) ? x:(-x);
while(x>0)
{
and = x & y;
xor = x ^ y;
while(and != 0 )
{
and <<= 1;
temp = xor ^ and;
and &= xor;
xor = temp;
}
x = xor;
}
if(x==0)
printf("%d is divisible by 3",tempvar);
else
printf(" %d is not divisible by 3",tempvar);
return 0;
}

Answer / siva prabhu

#include<stdio.h>

int main()
{
int x,y,i=0,j=0,r=0;
printf("enter a num\n");
scanf("%d",&x);

if(x>3)
{
while(x>0)
{
i=0;
while(i<3)
{
--x;
++i;
}
++j;
if(x<3)
{
r=x;
printf("reminder is %d\n",x);
break;
}
}
if(r==0)
printf("the given is divisible by 3\n");
else
printf("the given no. is not %% by %3\n");
}
else
{
printf("the given no. is not %% by %3\n");
}
return 0;
}

Answer / viral

#include<conio.h>
#include<stdio.h>
void main()
{
int a;
clrscr();

printf("enter the number ");
scanf("%d",&a);

if(a%3==0)
printf("the number %d is divisble by 3",a);
else
printf("the number %d is not divisible by 3",a);
getch();
}

regarding pointers concept

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