Scenario: There are 1 to 100 numbers. Each number should be
keep in the each column like from A column to Z column ie 1
to 26. From 27 to 52 should be in 2nd row in the excel
sheet. This has to be continue till 100. How do you write
Java program and what are various methods.
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Answer / ashwin khandelwal
public class NumPlacing {
int k=0;
int n=4;
int val=0;
int[]a=new int[101];
public void done(){
for(int j=0;j<n;j++){
if(val<101){
for(int i=0;i<26;i++){
val=val+1;
int count=i+1;
a[val]=val;
k++;
System.out.println(count+"->"+a[val]+"\t");
}
System.out.println("\n");
}
}
}
public static void main(String args[]){
NumPlacing num=new NumPlacing();
num.done();
}
}
| Is This Answer Correct ? | 8 Yes | 2 No |
Answer / vishal
public class NumberPlacing {
int k=0;
int n=4;
int val=0;
int[]a=new int[101];
public void printInTabularForm(){
int noOfRows = 100/26;
int rowStart = 1;
int setEnd = 26;
for(int i=rowStart; i<=setEnd; i++){
System.out.print(i+"\t");
if(i == 100){
break;
}else if(i==setEnd){
rowStart = i;
setEnd = i+26;
System.out.println();
}
}
}
public static void main(String args[]){
NumberPlacing num=new NumberPlacing();
num.printInTabularForm();
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / rupesh
package com.ab.Demo;
public class demo
{
public static void main(String[] args)
{
for (int i=1;i<=100;i++ )
{
if (i%26==0)
{
System.out.print(i+"\t");
System.out.println("");
}
else
{
System.out.print(i+"\t");
}
}
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / badrinath
int var=0,n=100/26;
for(int j=0;j<=n;j++){
for(int i=0;i<26;i++)
{ var=var+1;
if(var>100)
break;
System.out.print(var+"/");
}
System.out.println(); }
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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