4 years ago father was 9 times older than his son. after 2
years father was 42.what is the present age of his son and
father.
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Answer / indu
son's present age s 8,
if d fathers age is 42 after 2 yrs..then 4yrs before
he must be 36(4*9).
so that time d son's age s 4 and now 8.
Is This Answer Correct ? | 13 Yes | 4 No |
Answer / skumarcpr8
let present father & son age is X and Y
from Question after 2 years father age is X+2
X+2=42
X=42-2=40..............(1)
agin,
from Question ago 4years father age is (X-4) & son age is (Y-4)
X-4=9(Y-4)
or X-4=9y-36
or X-9y=-36+4
or 40-9y=-32 [from eq. (1) x=40]
or -9y=-32-40
or y=-72/-9
or y=8
so present father age is 40 & present son age is 8 years
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / angu ganesh
According to the question,
2 years after Father's age is 42.
So Present age of Father is 40 years explicitly.
4 years ago Father's age is 36. In this stage Father's age
is 9 times older than his Son. (ie) Father's age is equal
to 10 times of his Son's age.
10(Son's age) = Father's age
10x=36 => x=3.6 (ie) Four years ago, Son's
age is 3.6. Present age of son is 7.6 years
Answer. Father's age is 40 years.
Son's age is 7.6 years (7 years)
Is This Answer Correct ? | 0 Yes | 1 No |
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