1. Write a program that performs the following. The user
inputs a number and then enters a series of numbers
from 1 to that number. Your program should determine
which number (or numbers) is missing or duplicated in
the series, if any. For example, if the user entered
5 as the initial number and then entered the
following sequences, the results should be as shown.
Input Sequence Output
---------------------- ---------------
1 2 3 4 5 Nothing bad
However, if 7 were the high number, the user
would see the results on the right for the following
number entries:
Input Sequence Output
---------------------- ---------------
1 3 2 4 5 Missing 6
Missing 7
And if 10 were the high number and the user
entered the numbers shown on the left, note the list
of missing and duplicate numbers:
Input Sequence Output
---------------------- ---------------
1 2 4 7 4 4 5 10 8 2 6 Duplicate 2 ( 2 times)
Missing 3
Duplicate 4 ( 3 times )
Missing 9
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Answer / md. mohaiminul islam
#include <stdio.h>
#include <conio.h>
void main(void)
{
int a[100];
int s,c;
int b=0;
clrscr ();
printf("type lage number of your serise:\n");
scanf("%d",&c);
printf("Plz type how many numbers you want to check:\n");
scanf("%d",&s);
printf("Type the numbers you want to check\n");
for (int i=0;i<s;i++)
scanf("%d",&a[i]);
for (int x=1;x<=c;x++)
{
for (int y=0;y<s;y++)
if (a[y]==x)
b++;
if (b>=2)
printf("Duplicate %d :(%d) time's\n",x,b);
if (b==0)
printf("%d is missing.\n",x);
b=0;
};
getch ();
}
| Is This Answer Correct ? | 16 Yes | 12 No |
output for printf("printf");
hello friends, given an expression we have to remove the unwanted brackets in that expression. Eg : (a+b) ---> a+b (a+b)*(c)-----> (a+b)*c. Please mail me if you know the logic. My mail id is : saravana6m@gmail.com. Thank you in advance :-)
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C Code 
