Answer / patan

WE HAVE TABLE A (EID,ENAME,DEPT) AND TABLE B (NAMED,SID,DESIGNATION,SALARY)

--WE WANT TO RETRIEVE FOLLOWING
SELECT
B.NAMES AS NAMES
,B.DEPT AS DEPARTMENT
,B.SALARY AS SALARY
,B.DESIGNATION AS DESIGNATION

FROM TABLEA AS A
LEFT JOIN TABLEB AS B
ON A.EID=B.SID
ORDER BY B.NAMED


NOTE:WHEN WE ARE USING LEFT JOIN IT WILL MATCH THE RECORDS FROM BOTH THE TABLES AND LEFT TABLE OF RECORDS WILL DISPLAY...THAT ONLY I DID HERE

TRY IT..SURE IT WILL USEFUL

Answer / jayesh sonawane

this one correct try it:

SELECT
distinct
B.NAMES AS NAMES
B.SID
,B.DEPT AS DEPARTMENT
,B.SALARY AS SALARY
,B.DESIGNATION AS DESIGNATION

FROM TABLEB AS A join TABLEB AS b
on A.EID=B.SID and B.DEPT=A.DEPT and B.SALARY=A.SALARY and B.DESIGNATION =A.DESIGNATION
join TABLEA as taba on ON A.taba =B.SID

Answer / shankaranarayanan v

select eid,ename,dept,desg,salary from a,b
where a.eid=b.sid


(when a.eid=b.sid)

Answer / varunkumar

by using unions we can do it create two tables separetly and
apply union in between two tables .

Answer / litmus rav

If there is many to many relationship between two tables
then this will work,

you need to create thired table name A_B with attributes
eid references A(eid),sid references B(sid)

SELECT * FROM A,B,A_B WHERE A.eid=A_B.eid AND B.sid=A_B.sid
AND ORDER BY ename;

Answer / jeya

select Emp.* , sal.*
From Emp
Inner Join Sal On Emp.EmpId = sal.EmpId
Inner Join (
Select X.Department , sal.Designation , sal.salary
From Emp
Inner join (
Select Department
From emp Group By Department Having COUNT(*) > 1
)As X On X.Department = Emp.Department
Inner Join Sal On sal.EmpId = emp.EmpId
Group by X.Department , sal.Designation , sal.salary
Having COUNT(*) > 1
)as y on y.Department = emp.Department and y.Designation =
sal.Designation
and y.salary = Sal.salary

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