Answer / sriram

for comp-3 will store data in packed decimal format
s9(3)comp-3
0.5+1.5=2 bytes,
for 128 it will store c128 or f128.
for comp will store data in binary format
s9(2) will occupy 2 bytes
for 12 it will store binary format i.e 12=1100

Answer / kavithachandrashekar

comp-3 is stored as (n+1)/2 where n is number of digits.Since here n is 3 for numeric 128,(3+1)/2=2 bytes.

12 8C here c represents positive(D for negative)

Comp is stored as n/2,where n is number of digits.Since n is 2 for numeric 12,(2)/2=1 byte(1/2 word)
12 is saved as 12.

Answer / manohar reddy .d

n=128 it is a even number thaty (128/2)+1 65 in comp3


in comp s9(12) 8bytes it occupies

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