int main()
{
int i ,a[i];
i = 0;
a[i] = 10;
cout<< a[i] << endl;
return 0;
}
What will be output of this program?
Answers were Sorted based on User's Feedback
Answer / sachinmundhra
This will not get compile.
int i , a[i] ; // This statement will given error. Constant
expression required.
| Is This Answer Correct ? | 38 Yes | 3 No |
Answer / ramesh kumar
in array we can must enter size integer...
not as variable type like i
thats why it gives an error
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / mohammed afroz
There are compile time error in this program. Because array
can declare with a constant value.
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / vikas
Index variable of any array should be integer constant.
but in this case i is not constant so it is a error
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / rajesh
It will give segmentation fault(core dumped) - runtime error
This is not the way of declaring an array...a slight change
in program can correct it. Code below...
int main()
{
int i=0 ,a[i];
// i = 0;
a[i] = 10;
cout<< a[i] << endl;
return 0;
}
output : 10
please initialise the value of i before putting it in array
a[i]..this code will work fine and will give the output as 10.
| Is This Answer Correct ? | 3 Yes | 0 No |
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