Write a program that will count the number of digits in an
input integer up to value MAX_VALUE (2147483647). Thus, for
an input of 5837 the output should be
4 digits
Make sure that your program works for the numbers 0, 1, and
10. For the number 0, the output should be
1 digit
Answers were Sorted based on User's Feedback
Answer / usama azam
#include<iostream.h>
int main ()
{
int num;
cout<<"enter the number ";
cin>>num;
if (num>=0 && num<=9)
cout<<"You have entered one digit";
else if (num>=10 && num<=99)
cout<<"You have entered two digits";
else if (num>=100 && num<=999)
cout<<"You have entered three digits";
else if (num>=1000 && num<=9999)
cout<<"You have entered four digits";
else if (num>=10000 && num<=99999)
cout<<"You have entered five digits";
else if (num>=100000 && num<=999999)
cout<<"You have entered six digits";
else if (num>=1000000 || num<=9999999)
cout<<"You have entered seven digits";
system("pause");
return 0;
}
Is This Answer Correct ? | 6 Yes | 2 No |
Answer / sandeep mannarakkal
I have another suggestion for the above,
int iInputNumber;// This number is used for collecting input from user.
int nCount = 1;
while ( iInputNumber /10 )
{
iInputNumber = iInputNumber/10;
nCount ++;
}
cout << nCount << endl; // nCount will have the count of digits.
Is This Answer Correct ? | 0 Yes | 0 No |
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