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multiple of 9 without useing +,* oprator
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Answer / guest
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{clrscr();
int a,i,r=0;
scanf("%d",&a);
for(i=a;i>0;i--)
r=r-9;
r=abs(r);
printf("%d",r);
getch();
}
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / tknowledge05
The above guest is me .. okkkkk....
by the time i solved and executing i was logged out and when i posted the answer it considered guest............
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / jeke kumar gochhayat
this program is for any no
#include<stdio.h>
void main()
{
int n,k,c,l,i;
printf("enter the no");
scanf("%d",&n);
printf("which no of multiple u want");
scanf("%d",&l);
k=n;c=n;
for(i=1;i<l;i++)
{
while((n--)>0)
k++;
n=c;
}
printf("the multiple=%d",k);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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