Answer / parth ujenia

main()
{
char *ch="abcd";
char c[4];

for(int i=0;i<4;i++)
{
c[i]=*ch; //assign value to char c[i].
*ch++; //switch to next address of ch!
}

for(i=0; i<4 ;i++)
{
printf("%c - ",c[i]); //output will: a - b - c - d -
}

getch();

}

Answer / gopi

main()
{
char *ch="abcd";
char c[4];

for(int i=0;i<4;i++)
{
c[i]=*ch;
ch++;
}


printf("%s",c);

getch();

}

Answer / wade stone

#include <stdio.h>
#include <string.h>

using namespace std;

int main( )
{
char *ch = "abcde";
char c[4];

memcpy( c, ch, sizeof( c ) );

return 0;
}

Answer / supriya pandey

i think we used the string libruary function strcpy() to
copy it...

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