How many joins in Informatica

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How many joins in Informatica..

Answer / ravindra.15aug

Normally four joins in Informatica
1) Normal join
2) Master join
3) Detail join
4) Full outer join

Is This Answer Correct ?    38 Yes 2 No

How many joins in Informatica..

Answer / sanjaygupta1981

The Informatica supports the following types of joins:
• Normal
• Master Outer
• Detail Outer
• Full Outer

Normal join: discards all the rows of data from the master
and detail source that do not match, based on the condition.

SELECT * FROM employees, departments WHERE
employees.department_id = departments.department_id

Master outer join: discards all the unmatched rows from the
master source and keeps all the rows from the detail source
and the matching rows from the master source.

SELECT * FROM employees LEFT OUTER JOIN departments ON
(employees.department_id = departments.department_id)

Detail outer join: keeps all rows of data from the master
source and the matching rows from the detail source. It
discards the unmatched rows from the detail source.

SELECT * FROM employees RIGHT OUTER JOIN departments ON
(employees.department_id = departments.department_id)

Full outer join keeps all rows of data from both the master
and detail sources.

SELECT * FROM employees FULL OUTER JOIN departments ON
(employees.department_id = departments.department_id)

Is This Answer Correct ?    23 Yes 1 No

How many joins in Informatica..

Answer / srinivas

there are four types of joins in Informatica
1) Normal join
2) Master join
3) Detail join
4) Full outer join

Is This Answer Correct ?    13 Yes 2 No

How many joins in Informatica..

Answer / srinivas

there are four types of joins in Informatica
1) Normal join -- Equi join
2) Master join -- Left outer join
3) Detail join -- Right outer join
4) Full outer join -- Full outer join

Is This Answer Correct ?    9 Yes 7 No

How many joins in Informatica..

Answer / maj

In this select query I think instead of LEFT OUTER
JOIN,Need to put "RIGHT OUTER JOIN"

SELECT * FROM employees LEFT OUTER JOIN departments ON
(employees.department_id = departments.department_id)

Is This Answer Correct ?    3 Yes 2 No

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