if a and b are mixed in 3:5 ration and b,c are mixed in 8:5
ration if the final mixture is 35 litres, find the amount
of b in the final mixture
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Answer / anu
ans is 15.73lts
a/b=3:5
b/c=8:5
a=3 b=8*5/5==>b=5; c=5*5/8==>25/8
hence a=3 b=5 c=25/8
multipying by 8
becomes a=24 b=40 c=25
Now,
Ingredient a
---------------------
(24/89) x 35 = 9.44 litres
Ingredient b
---------------
40/89 x 35 = 15.73 litres
Ingredient c
--------------------
25/89 x 35 = 9.83 litres
So b=15.73 lts
| Is This Answer Correct ? | 91 Yes | 9 No |
Answer / manju
a/b=3*8/5*8 and b/c=8*5/5*5 a/b/c=24:40:25
ans=40*35/(24+40+35)=1400/89
Ans=15.79}
of b in the final mixture
| Is This Answer Correct ? | 22 Yes | 8 No |
Answer / vignesh
a/b=3/5,b/c=8/5.
a/(a+b)=3/8,b/(b+c)=8/13
a=((a+b)*3)/8-----1
(b+c)=13*b/8------2
a+b+c=35-----3
substituting the value 1&2 in 3
(((a+b)*3)/8)+13*b/8=35
finally we get
3a+16b=280-----4
solving one we get
5a-3b=0-----5
multiplying eqn 4 by 5 and eqn 5 by 3,we get,subtracting 4&5
15a+80b=1400
15a+9b=0
we get b=15.73
| Is This Answer Correct ? | 8 Yes | 1 No |
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