main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(

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main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
}

Question Posted / karthik

5 Answers
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main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }..

Answer / s k dubey

hello ,if problem is..
int *p=(int*)malloc(sizeof(int));
*p=4;
printf("%d",(*p)+++(*p)++);

o/p is 9;

it is just similar the case of post incremental operation of
variable like i+++i++.

Is This Answer Correct ?

158 Yes

14 No

main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }..

Answer / vishnu

hi all,
i think *ptr=(int*)malloc(size of (int));
*ptr=4;
mean malloc(size of (int)) is used to allocate memory of only 4.
hence(*ptr)+++*ptr++)=4+4=8

Is This Answer Correct ?

28 Yes

43 No

main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }..

Answer / ankit panwar

*ptr++ : it just increments the pointer not the value it is
pointing to..

++*ptr : it increments the value the pointer points to but
not the pointer..

here

(*ptr++) + (++*ptr) = 0 + (4+1) = 5

so the answer will definately be 5

Is This Answer Correct ?

2 Yes

31 No

main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }..

Answer / aravind

I think it gives syntax error because there is no operation in C which says P+++ just P++.If he can seperate that one + than the above ans is will be 5+5=10.

Is This Answer Correct ?

5 Yes

35 No

main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }..

Answer / manil shrama

hello all..........
here malloc function reserves a memory space for an integer,whose adddess is pointed by integer pointer p.
Now at this memory space,4 istored by using *p = 4

(*p)+++means,*p=*p+2, (4+2=6)
and ptr++ means,*ptr=*ptr+1, (4+1=5)

now 4*5=30 is required answer
k bye.....tc

Is This Answer Correct ?

6 Yes

49 No

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