write a program that a 5 digit number and calculates 2
power that number and prints it.
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Answer / ayushi rastogi
/* We assume that user enter 5 digit No */
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
double No,length=2;
double pwrNo;
printf("Please Enter the 5 digit No.:");
printf("\n");
scanf("%d",&No);
pwrNo=pow(No,2);
printf("\n");
printf("Power of %u No is %u",No,pwrNo);
}
| Is This Answer Correct ? | 6 Yes | 5 No |
Answer / umesh
// This will yield the result if user enters only 5 digit
number.
//import headers
class power
{
public static void main(string args[])
{
system.out.println("Enter 5 digit number : ");
n = system.in.readline();
b =0;
len = n.length();
if(len == 5)
{
a=Integer.ParseInt(n)
for i=0;i<a;i++
{
b = 2*2;
}
system.out.println("2 power entered 5 digit number is :
"+b)
}
else
{
system.out.println("Entered number in more/less than
5 digits")
}
}
//Sorry, not much familiar about the syntax.. but here is
the logic..
| Is This Answer Correct ? | 3 Yes | 6 No |
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