Answer / devendra lohiya

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k,l,sp=7;
clrscr();
for(i=1,k=1;i<5;i++)
{
for(l=1;l<sp;l++)
printf(" ");
sp-=2;
printf(" ");
for(j=1;j<=i;j++,k++)
{
printf(" ");
printf("%d",k);
printf(" ");
}
printf("\n");
}
getch();
}

Answer / sudhanshu kumar

#include<stdio.h>
#include<conio.h>

void main()
{
int nol,i,j,k=1,l=1;
clrscr();
printf("Enter the no. of line: ");
scanf("%d",&nol);
for(i=nol*2;i>=2; i=i-2)
{
printf("\n\n");
for(j=1;j<=i;j++)
printf(" ");

for(j=1;j<=l;j++)
printf("%2d ",k++);
l++;
}
getch();
}

Answer / gaurav singh

In c++ u can write like this

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i,j=0,k=1,s=0;
cout<<"pattern \n";
for(i=1;i<=4;i++)
{
for(s=4-i;s>0;s--)
{
cout<<" ";
}
for(j=i;j>0;j--)
{
cout<<k;
k++;
cout<<" ";
}
cout<<"\n";
}

getch();
}

Answer / mini

#include<stdio.h>
#include<conio.h>
main()
{
int i,n;
printf("enter the number to n")
scanf(%d,\n)
i=1,i++;
i<=10;
printf("he result is \i")
getch();
}

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