any body prove that is 2 = 1
two = one ?
Challengeable task .
Answers were Sorted based on User's Feedback
Answer / qwertz
There is no such proof.
Any body should know that you can't cancel zero, or divide
by zero.
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / karteekkarteek001
consider a2-b2=(a+b)(a-b) ( a2 mean a square.)
put a=b, then
b2-b2=(b+b)(b-b)
b(b-b)=(b+b)(b-b) (take b common on LHS of the equation)
1b= 2b ( b-b) get cancled on both side
1=2 b also get cancled on both side.
In line #4, you can not cancelled the (b-b) terms on both
sides, it's a fallacy!
If you cancel (b-b) terms, it like cancelling zeros on both
sides.
Then all the numbers will become equal to each other...
1=2=3=4=5=6=7=8=9=10=....
Anyways nice to see your answer!
Is This Answer Correct ? | 4 Yes | 3 No |
Let two =2
Let one = 1
Let the average (mean) of one and two = Ave
Then one + two = 2Ave
Rearranging;
two = 2Ave - one
and two – 2Ave = -one
multiplying both side by two or its equal
two(two – 2Ave) = -one(-one + 2Ave)
two2 – 2xtwox2Ave = one2 – 2 x one x Ave
Add Ave2 to both sides
two2 – 2x one x Ave + Ave2 = one2 -2 x one x Ave + Ave2
(two - Ave)2 = (one - Ave)2
Take the square root of both sides
two - Ave = one - Ave
Add Ave to both sides
two = one
Is This Answer Correct ? | 1 Yes | 0 No |
Answer give by math genius Karteekkarteek001
consider a2-b2=(a+b)(a-b) ( a2 mean a square.)
put a=b, then genius you have
b(b-b)=(b+b)(b-b)= b(0)=b+b)(0)
0 = 0 great answer
The rest of this is garbage
(take b common on LHS of the equation)
1b= 2b ( b-b) get cancled on both side
1=2 b also get cancled on both side.
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ranganathappa c
consider a2-b2=(a+b)(a-b) ( a2 mean a square.)
put a=b, then
b2-b2=(b+b)(b-b)
b(b-b)=(b+b)(b-b) (take b common on LHS of the equation)
1b= 2b ( b-b) get cancled on both side
1=2 b also get cancled on both side.
Is This Answer Correct ? | 6 Yes | 9 No |
Answer / gupta ji
i will answer after some time if any body wants then
contact to me on personl mail i.d
happynmahe@hotmail.com
Is This Answer Correct ? | 2 Yes | 7 No |
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