Answer / varun vithalani

I am working on the answer now but i can say that answer 1
and 2 are absolutely wrong. I haven't checked the 3rd yet.
In 1 and 2 solutions, it only looks for the first character
of the needle and does not care about the remaining.

For example:
haystack = "sweetsugar"
needle = "sugar"

It will return value '0' since it matches the first 's' of
'sweetsugar' and 'sugar'. The answer should be '5'.

Answer / anand

int stripos ( char* haystack, char* needle, int offset )
{
char *ptr;
ptr=haystack;
int pos=0;
while ( *ptr!='\0' )
{
if( *ptr == *needle )
return pos;
pos++;
ptr++;
}

return -1;
}

this function written for exact match of the charecter and
dosent bother for whatever is offset.

Answer / anand

int stripos ( char* haystack, char* needle, int offset )
{
char *ptr,X,Y;
int diff = 'A'-'a' ,pos=0;

ptr=haystack;
X=(*needle>='A' && *needls<='Z')?*needle-diff:*needle;
while ( *ptr!='\0' )
{ Y=(*ptr>='A' && *ptr<='Z')? *ptr-diff : *ptr )
if( Y == X )
return pos;
pos++;
ptr++;
}

return -1;
}

int offset is of no use in the function. however, the
question does not give any details of offset parameter. even
if provided the function may not require as all strings end
with NULL character ( same as '\0' ).

*needle is converted to small case letter and is compared
with converted small letter of the string.

Answer / anand kanawally

int stripos ( char* haystack, char* needle, int offset )
{
char *ptr;
ptr=haystack;
int pos=0;
while ( *ptr!='\0' )
{
if( *ptr == *needle )
return pos;
pos++;
ptr++;
}

return -1;
}

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