Answer / sreejesh1987

step 1:Declare the variables needed.
step 2: Get the String in a String variable
step 2:Use a for loop to reverse the string.
step 3:Display the elements of the string from last element
to first element.

Answer / sudip chatterjee

1. Start.
2. Declare Array str1[25], str2[25] as an alphanumeric.
3. Declare i, g, l, as numeric.
4. Assign or accept value to Str1.
5. l=i=0;
6. while(str1[i]!="/0")["/0"last index point that u entered.]
a.increase i, l by 1;
7. Repeat steps i,ii, iii for j from o
i. str2[j]= str1[i-1]
ii. increase j by 1.
iii. decrease i by 1.
8. str2[j]="/0" .
9. Display str2
10. Exit.

Complexity T(n) What is the time complexity T(n) of the following portions of code? For simplicity, you may assume that n is a power of 2. That is, n = 2k for some positive integer k. a) ? for (i = 1; i <= n; i++) { j = n; cout << i << ? ? j << ? ? << endl; } b) ? for (i = 0; i <= n; i += 2) { j = n; cout << i << ? ? j << ? ? << endl; } c) ? for (i = n; i >= 1; i = i/2) { j = n; cout << i << ? ? j << ? ? << endl; } d) for (i = 1; i <= n; i++) { j = n; while (j >= 0) { cout << i << ? ? j << ? ? << endl; j = j - 2; } }

0 Answers   Qatar University,

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0 Answers   ASD Lab, Qatar University, UNV,

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