Answer / sujan_faith

<!--i have just replaced the same array element with
the value zero but alse we can destroy that element-->>


#include<iostream>
#define size 10
using namespace std;

int main()
{
int a[10]={10,10,10,2,1,1,1,1,1,2};
int j=1;
for(int i=0;i<size;i++)
{
for(int k=i+1;k<size;k++)
{
if(a[i]==a[k]&&a[i]!=0)
{
a[k]=0;
j++;

}
if(k==(size-1)&& a[i]!=0)
cout<<"Value is: "<<a[i]<<" which is repeated "<<j<<" times"<<endl;
}
j=1;
}
system("pause");
}

Read the following program carefully and write the output of the program. Explain each line of code according to given numbering. #include <stdio.h> #include <unistd.h> #include <stdlib.h> #include <errno.h> 1……………… int main (void) { pid_t pid; 2………………………… pid = fork(); 3…………………………. if (pid > 0) { int i; 4………………………… for (i = 0; i < 5; i++) { 5………………… …………… printf(" I AM VU : %d\n", i); 6………………… …………… sleep(1); } exit(0); } 7………………… ……… else if (pid == 0) { int j; for (j = 0; j < 5; j++) { 8……………………………… printf(" I have no child: %d\n", j); sleep(1); } _exit(0); } else { 9………………………………fprintf(stderr, "can't fork, error %d\n", errno); 10……………… … ………… exit (EXIT_FAILURE); } }

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