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How can we initialize a variable which is a constant in a
LDA. Suppose I want to declare a variable #a N1(1:7) having
constant values as 1,2,3,4,5,6, and 7 for respective
occurance then how can we do that?
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Answer / dipti karale
In data area editor screen, define the variable #a with
Format "N" and length 1. Then edit this variable/ field by
typing in a ".e" just before the level number of this
variable. This will take you the "Extended Field Definition
Editing screen". Type the code as "A" for Array index
definition. On the "Index definition" screen, declare your
index as 1:7 press enter and exit the screens until you are
back onto the data area editor screen.Now again type in
a ".e" to edit the same field/ variable and type code "S"
for defining the single initial values. On this initial
value screen, change the "Define as Constant" field value
from "N" (No) to "Y" (yes)and just below it define constant
values against each index value ranging from 1 to 7.
| Is This Answer Correct ? | 8 Yes | 2 No |
Answer / daniel
You do something like:
#a (n1(1:7) init (1) <1>
(2) <2>
(3) <3>
(4) <4>
(5) <5>
(6) <6>
(7) <7>
| Is This Answer Correct ? | 8 Yes | 5 No |
Answer / kalyan
in the LDA against the field give .e, another screen will
be displayed. there give "S" for CODE, another screen will
be displayed there we need to give the constant values.
come back and save & stow the lda.
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / joydeep chakrabarty
In your program editor, type:
1 #A (N1/1:7) INIT(v) <1,2,3,4,5,6,7>
Thanks.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / rockys
Tricky part is 'LDA" . You need to use 'Initial values and
Edit mask' menu to initialize an array in LDA as there not
enough space on right hand side .
| Is This Answer Correct ? | 1 Yes | 5 No |
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