Answer / md abdul khader

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int n,a[100],b[100],i,test=0,j,count=0;
cout<<"The size of your digit : ";
cin>>n;
cout<<"Enter the digits of your number : "<<endl;
for(i=0;i<n;i++)
{
cin>>a[i];
}
for(j=0;j<=9;j++)
{
for(i=0;i<n;i++)
{
if(a[i]==j)
count++;
}
b[j]=count;
count=0;
}
cout<<"Your number is : ";
for(i=0;i<n;i++)
{
cout<<a[i];
}
cout<<"\nDesired Output is : "<<endl;
for(i=0;i<=9;i++)
{
cout<<i<<" : ";
while(test<b[i])
{
cout<<"* ";
test++;
}
test=0;
cout<<endl;
}
getch();
}

Answer / vikky_manit

#include<stdio.h>
void main()
{
int a[10],n,key,count=0;
printf("Enter the number of elements\n");
scanf("%d",&n);
printf("Enter %d elements\n",n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("Enter the element whose frequency is to be
determined\n");
scanf("%d",key);
for(i=0;i<n;i++)
if(key==a[i])
count++;
printf("Frequency=%d",count);
}

Answer / veeraj.j

#include<stdio.h>
void main()
{
int a[10],n,key,count=0;
printf("Enter the number of elements\n");
scanf("%d",&n);
printf("Enter %d elements\n",n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("Enter the element whose frequency is to be
determined\n");
scanf("%d",&key);
for(i=0;i<n;i++)
if(key==a[i])
count++;
printf("Frequency=%d",count);
}

Answer / pratik roy

#include<stdio.h>
#include<conio.h>

void freq(int ,int ,int );

int main()
{
int a,key,count,i;
printf("Enter the elements\n");
scanf("%d",&a);
printf("Enter the element whose frequency is to be determined\n");
scanf("%d",&key);
freq(a,key,0);
getch();
return 0;
}

void freq(int num,int key,int count)
{
int samkey,i;
i=num/10;
if(i!=0)
{
samkey = num%10;
if(samkey == key ) {count++; freq(num,key,count);}
else
{
num=num/10;
freq(num,key,count);
}
}
printf("%d",count);
}

.find the output of the following program? char*myfunc(char*ptr) { ptr +=3; return (ptr); } int main() { char*x,*y; x="HELLO"; y=myfunc(x); printf("y = %s ",y); return 0; }

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