Answer / anuj pratap singh

#include<stdio.h>
#include<conio.h>
void sort(int *,int );//prototype
void main()
{
int a[5],size=5; //let suppose
int i;
clrscr();
printf("Enter the elements according to size:");
for(i=0;i<size;i++)
{
scanf("%d",&a[i]);
}
sort(a,size); //calling function
printf(\n\npress any key to exit);
getch();
}
void sort(int *p,int size) //called function
{
int i,j,temp;
for(i=0;i<size-1;i++)
{
for(j=0;j<size-i-1;j++)
{
if(*(p+J)>*(p+j+1))
{
temp=*(p+J);
*(p+J)=*(p+J+1);
*(p+J+1)=temp;
}
}
}

for(i=0;i<size;i++)
{ pritf("%d",*(p+i));
}
}

Answer / gulam md gouss khan

#include<stdio.h>
#include<conio.h>
void sort(int *,int );//prototype
void main()
{
int a[5],size=5; //let suppose
int i;
clrscr();
printf("Enter the elements according to size:");
for(i=0;i<size;i++)
{
scanf("%d",&a[i]);
}
sort(a,size); //calling function
printf(\n\n press any key to exit);
getch();
}
void sort(int *p,int size) //called function
{
int i,j,temp;
for(i=0;i<size-1;i++)
{
for(j=0;j<size-i-1;j++)
{
if(*(p+J)>*(p+j+1))
{
temp=*(p+J);
*(p+J)=*(p+J+1);
*(p+J+1)=temp;
}
}
}

for(i=0;i<size;i++)
{ pritf("%d",*(p+i));
}

Answer / nitish-csedu

#include<stdio.h>
int main()
{
int n,i,j,temp,a[1000],*p;
scanf("%d",&n);
p=&a[0];
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n-1;i++)
{
for(j=i+1;j<n;j++)
{
if(*(p+i)>(*(p+j)))
{
temp=*(p+i);
*(p+i)=*(p+j);
*(p+j)=temp;
}
}
}
for(i=0;i<n;i++)
{
printf("%d ",*(p+i));
}
return 0;
}

If you know then define #pragma?

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3 Answers  

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What is wrong with this code?

0 Answers  

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