Answer / monalisa.dalbehera

select count(s.student_id),c.cource_name
from student s,course c
where c.course_id=s.course_id
group by c.course_name;

Answer / pradip d

select count(student_name),course_name from student,course
where course.course_id=student.course_id group by course_name;

Answer / kalyan

SELECT COURSE_NAME,COUNT(B.STUDENT_ID) NO_OF_STUDENTS
FROM COURSE A LEFT OUTER JOIN STUDENT B
USING (COURSE_ID)
GROUP BY A.COURSE_NAME

OR

SELECT COURSE_NAME,COUNT(B.STUDENT_ID) NO_OF_STUDENTS
FROM COURSE A , STUDENT B
WHERE A.COURSE_ID = B.COURSE_ID(+)
GROUP BY A.COURSE_NAME

This will list all the courses with no of students

Answer / neo28

select Course_Id, Course_Name, count(Student_id) from
(
select c.Course_Id, c.Course_Name, s.Student_id
from Student s, Course c
where s.Course_Id(+) = c.Course_Id
) group by Course_Id
order by Course_Id;

Answer / iamanocp

select c.course_id, count(s.student_id)
from student s, course c
where s.course_id = c.course_id
group by c.course_id;

Answer / lova raju allumalla

select count(stud_name),course_name from student s,course c
where s.course_id = c.course_id group by course_name
/

Answer / cm

select s.stud_name,c.course_name from student s,course c
where s.course_id = c.course_id group by
s.stud_name,c.course_name;

Answer / dinakar

select course_id,count(*) from student where course_id in
(select course_id From course)
GROUP BY COURSE_ID

Answer / guest

select count(student_id),course_name ,student_name
from student s, course c
where s.course_id = c.course_id
group by course_id
order by student_id desc

Answer / chinnu

SELECT *(Courses,students) FROM Table Student

What are the operators used in select statements?

0 Answers  

how to create table with in the procedure or function?

2 Answers   Genpact, HCL,

Why do we need view in sql?

0 Answers  

if we give update table_name set column_name= default. what will happen?

4 Answers   iFlex,

what is purge command explain about oracle performance tuning

2 Answers   Accenture, eCentric Solutions,

Do ddl statements need commit?

0 Answers  

what is the correct way of selection statement a. select/from/table_name/orderby/groupby/having b. select/from/table_name/groupby/having/orderby

5 Answers   HCL, JPMorgan Chase,

How many types of literals are available in pl sql?

0 Answers  

Hi, I am new in oracle(SQL), could anyone help me in writing a correct SQL. Below is the table structure. Table: Subsc Fields: 1. Sub_no (this field will hold values of subscriber nos, for e.g. S111111, S222222, S333333, S444444, etc.) 2. s_status (this field will hold values for different status of subscriber, for e.g. 'A', 'S', 'C', etc.) 3. cus_id (this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) Table: Bill Fields: 1. Bill_no this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) 2. b_status = (this field will hold values for different status of bill for e.g. 'O', 'C', 'S', etc.) Note: 1. The Sub_no is a Primary key of Subsc table. 2. The cus_id is a foreign in Subsc table (referred from Bill_no field of Bill table) 3. The Bill_no field is the Primary key of Bill table. Query A --> I wrote a query to select cus_id/Bill_no which is in status open (b_status = 'O') and having more than two active subscriber (i.e. S_status = 'A') in it ( i.e. more the two subscribers in same bill). select s.cus_id from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id having count(sub_no) = 2 Problem : The above query will give the cus_id (or rather bill_no) which are in open status (b_status ='O) and which are having TWO ACTIVE Subscribers (s_status ='A') in it. However, this query will also lists the cus_id/bill_no which are having more than TWO subscribers in it (but only two subscriber will be in Active status (s_status = 'A') and the others will be in s_status = 'C' or s_status = 'S'. Help needed: I want to write a query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it. B--> If I include the sub_no in the above query then NO row are returned. select s.cus_id, s.sub_no from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id, s.sub_no having count(sub_no) = 2 Help needed: I want to modify the above query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it ALONG with the sub_no. Thanks a lot in advance. Regards, Nitin

0 Answers  

Can a varchar be a primary key?

0 Answers  

What is a constraint. Types of constraints ?

5 Answers   Accenture, BirlaSoft,

What is autocommit sql?

0 Answers