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Link list in reverse order.

Answer Posted / shruti

//Go through the code, incase any issues feel free to
revert.

Copying a link list:

//home is the stationary pointer of the main linked list
which is to be copied.

//head is the stationary pointer of the new linked list
which has to be created..

//temp and temp1 are the moving pointers attached to the
respective linked list...


struct node *copy(struct node *home , struct node *head)
{
struct node *temp , *temp1 , *p;

temp = home;
while(temp != NULL)
{
p = (struct node *) malloc (sizeof(struct node));
p -> data = temp -> data;

if(head == NULL)
head = p;

else
{
temp1 = head;
while(temp1 -> next != NULL)
temp1 = temp1 -> next;

temp1 -> next = p;
}
temp = temp -> next;
}
return head;
}

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