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What will be the result of the following program?
main()
{
char p[]="String";
int x=0;
if(p=="String")
{
printf("Pass 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
else
{
printf("Fail 1");
if(p[sizeof(p)-2]=='g')
printf("Pass 2");
else
printf("Fail 2");
}
}
a) Pass 1, Pass 2
b) Fail 1, Fail 2
c) Pass 1, Fail 2
d) Fail 1, Pass 2
e) syntax error during compilation
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Answer Posted / shruti
syntax error during compilation..
we cannot compare strings using if(p == "string")
so will not work..
NOTE:
while comparing string otherwise also we use 'string'
(string in single quotes ' ' not " ")..
| Is This Answer Correct ? | 0 Yes | 2 No |
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