Interested to Buy Any Domain ? << Click Here >> for more details...
As the system administrator, you enter the following commands at
the command prompt:
ipx routing
access-list 800 permit 2b 4d
int e0
ipx network 4d
ipx access-group 800 out
int e1
ipx network 2b
int e2
ipx network 3c
What did these command accomplish?
A. Traffic from network 4c destined for network 4d will be
forwarded out
Ethernet0.
B. Traffic from network 3c destined for network 4d will be
forwarded out
Ethernet0.
C. Traffic from network 2b destined for network 4d will be
forwarded out
Ethernet0.
D. Traffic from network 4d destined for network 2d will be
forwarded out
Ethernet0.
- 1 Answers
- 4007 Views
- I also Faced
- E-Mail Answers
Answer Posted / guest
Answer: C
Traffic from network 2b destined for network 4d will be
forwarded out
Ethernet0. The other interfaces E1 and E2 are not subject to
the access
list since they lack the access group statement to link them
to access
list 800.
| Is This Answer Correct ? | 1 Yes | 0 No |
Post New Answer View All Answers
What is the meaning of synchronization?
What is the different between console port and auxiliary port?
Explain how many types of ends in wan?
Why we use filter option?
How do you configure a Cisco router to route IPX?
Explain the matric of eigrp protocol?
what does PPTP use for encryption and authentication?
Explain on which interface we always apply access-list?
What is a Frame Relay?
Do you know how many types of data?
How network gateway is different from routers?
What is ‘round-trip time’?
What is the difference between static and dynamic ip addressing?
What is difference between flsm and vlsm?
What is the difference between hub, switch, and router?
