Answer Posted / jayasree
yes, it is possible.
A2-b2 = (a+b) (a-b) as equn 1
Lets take b2=a, substitute in equn 1,
A2-a =(a+b) (a-b)
A2-a = a2-ab+ab-b2
-a = -b2
A=b2
Take log on both sides,
Log a = 2 log b
Assume a=b=0, and subsitute,
Log 0 = 2 log 0
1 = 2 (1) (i.e, log 0 = 1)
1=2
| Is This Answer Correct ? | 2 Yes | 2 No |
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