How do you sort a Linked List (singly connected) in O(n)
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Answer Posted / ajaay
struct NODE
{
int nodevalue;
struct NODE *next;
}
struct NODE *uslist, *slist;
struct NODE *cur_us, *cur_s; /*pointers to surf the lists*/
main()
{
..
/*uslist and slist have been initialised here*/
/*uslist holds the list to be sorted*/
/*slist is initially empty as nothing is sorted*/
..
..
LLsort();
}
LLsort ( )
{
int delval;
struct NODE *temp;
slist->nodevalue = 0; /*sorted list will have 0 as its first
element initially*/
slist->next = NULL;
cur_us = uslist;
while( cur_us != NULL)
{
cur_s = slist;
while(cur_s != NULL)
{
if(cur_us->nodevalue < cur_s->nodevalue) /*step-1 of
the algo.*/
{
target = cur_s; /*step-2: make cur_s as your TARGET*/
delval = delnode(cur_us); /*deletion has to be done to
the UNSORTED list*/
addnode(delval, target); /*remember addition has to be
done to the SORTED list*/
}
else
if(cur_s->next == NULL) /*step-3:if cur_s is the last
element in the sorted list*/
{
delval = delnode(cur_us);
temp_us = (struct NODE *)malloc(sizeof(NODE));
temp_us ->nodevalue = delval;
cur_s->next = temp_us; /*step-3:append the
unsorted element to the sorted list*/
temp_us->next = NULL;
}
cur_s = cur_s->next;
}
cur_us = cur_us->next;
}
}
| Is This Answer Correct ? | 3 Yes | 11 No |
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