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f(*p)
{
p=(char *)malloc(6);
p="hello";
return;
}
main()
{
char *p="bye";
f(p);
printf("%s",p);
}
what is the o/p?
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Answer Posted / fazlur rahaman naik
actually the above programme produces an error.because u've
to mention which type of pointer it is at fuction f(*p).
i.e f(char *p).
if u correct this error.then the out put will be
bye
| Is This Answer Correct ? | 4 Yes | 1 No |
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