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If we have 9 floor n 3 eggs n we have to check from which floor the egg wont get break.how can we do that
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Answer Posted / saurabh dhande
To find the floor from which the egg won't break, you can use a modified binary search algorithm. Here's a step-by-step explanation of the process:
Divide the building into intervals: Begin by dropping an egg from the middle floor (floor 5 in this case if there are 9 floors) using the first egg. If it breaks, then you know the critical floor must be below this floor. If it doesn't break, then you know the critical floor must be above this floor.
Determine the next interval: Based on the result of the first drop, you now have two sub-intervals left to explore. If the egg didn't break in the first step, you will drop it from the middle floor of the upper sub-interval (floors 6 to 9 in this case). If it breaks, you know the critical floor is one of these upper floors. If it doesn't break, the critical floor must be one of the lower floors (floors 1 to 4).
Continue dividing the intervals: Repeat the process until you narrow it down to a single floor. To do this, you will use the second egg as a safety net in case the critical floor is at the very top. This way, you minimize the number of egg drops required.
By following this approach, you should be able to find the critical floor with the minimum number of egg drops. The maximum number of attempts required using this method is 4 in the worst-case scenario.
In this specific example with 9 floors and 3 eggs, you can find the critical floor in at most 4 attempts.
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