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main()
{
int x=20,y=35;
x = y++ + x++;
y = ++y + ++x;
printf("%d %d\n",x,y);
}
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Answer Posted / muhammad abdullah
#include<stdio.h>
#include<conio.h>
void main()
{
int x=20,y=35; (comment)//We delcare two variables and initialize them.
clrscr();
x=y++ + x++; (comment) /*As increment operator increases one in the value of variable.The value
of y is 35 and after increment of 1, the value of y will be 36.The value of
x=20 and after increment of 1, the value of x will be 21.Arithmetic operator
(+) adds both the values(36+21=57).So, the value of x=57.*/
y=++y + ++x; (comment) /*The value of y is 35.Due to increment operator the value of
y becomes 36.And we have ever got the value of x as it is x=57. Now,increment
operator add 1 in the value of x and the value of x will be 58.By adding
(36+58=94) we got the final value of y=94.*/
printf("The value of x=%d
The value of y=%d
",x,y);
getch();
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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