A cylindrical wire is compressed in length by 10%. The
percentage decrease in the resistance will be?????
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Answer Posted / ashlesha
R=p*l/A
Length is decreased by 19% so
L'= 90%of l
=0.9l
Volume remains the same and area increased by 10%
So, new area=1.1A
R=0.9l/1.1A=081R
Change in resistance=1-0.81
=0.19
0.19=19%
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