Answer Posted / ritesh pal
The simplest and most obvious way to specify an action in C++ is to write a function. However, if the action has to be delayed, has to be transmitted 'elsewhere' before being performed, requires its own data, has to be combined with other actions, etc then it often becomes attractive to provide the action in the form of a class that can execute the desired action and provide other services as well.
Manipulators used with iostreams is an obvious example.
Explanation:
A common form of action class is a simple class containing just one virtual function.
class Action
{
public:
virtual int do_it( int )=0;
virtual ~Action( );
}
Given this, we can write code say a member that can store actions for later execution without using pointers to functions, without knowing anything about the objects involved, and without even knowing the name of the operation it invokes. For example:
class write_file : public Action
{
File& f;
public:
int do_it(int)
{
return fwrite( ).suceed( );
}
};
class error_message: public Action
{
response_box db(message.cstr( ),"Continue","Cancel","Retry");
switch (db.getresponse( ))
{
case 0: return 0;
case 1: abort();
case 2: current_operation.redo( );return 1;
}
};
A user of the Action class will be completely isolated from any knowledge of derived classes such as write_file and error_message.
| Is This Answer Correct ? | 0 Yes | 0 No |
Post New Answer View All Answers
Define the process of handling in case of destructor failure?
What are the differences between new and malloc?
Differentiate between structure and class in c++.
What do you mean by inheritance in c++? Explain its types.
Where can I run c++ program?
How do you write a function that can reverse a linked-list?
What is class and structure in c++?
What is recursion?
Difference between a homogeneous and a heterogeneous container
How can I learn c++ easily?
What are libraries in c++?
Explain binary search.
Why is main an int?
Which one between if-else and switch is more efficient?
What are c++ storage classes?