In int at least 2 bytes are used for size and we know that &ptr[] gives

main()
{
int ptr[] = {1,2,23,6,5,6};
printf("%d",&ptr[3]-&ptr[0]);
}

Question Posted / dipak

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Answer Posted / dipak

In int at least 2 bytes are used for size and we know that &ptr[] gives the address of ptr .
&ptr[3]-&ptr[0]
Size of &ptr[3] is 3*2=6 times greater than Size of &ptr[0] is 1*2=2
ptr[0] also have any value that's why I consider it 1
So 6-2=4

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