Answer Posted / kangchuentat

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 16 : E. Two combinations are possible, either (3 students + 3 teachers) or (4 students + 2 teachers). Number of ways = 8C3 x 6C3 + 8C4 x 6C2 = (8!) / [ (3!) (5!) ] x (6!) / [ (3!) (3!) ] + (8!) / [ (4!) (4!) ] x (6!) / [ (4!) (2!) ] = 2170. Excel language is =fact(8)/(fact(3)*fact(5))*fact(6)/(fact(3)*fact(3))+fact(8)/(fact(4)*fact(4))*fact(6)/(fact(4)*fact(2)), which is also equal to 2170.

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