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A can do a piece of work in 20 days.B can do the same in 15 days.they both together work for 6 days,then B is replaced by C who works with A for next 4 days & finished it.in how many days C alone can do the same work?
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Answer Posted / dipesh
Work done by A in one day is 1/20
Work done by B in one day is 1/15
Work done by A and B in 6 days is (1/20+1/15)*6
Work done by A and C in 4 days is (1/20+1/x)*4 // assuming that C does the complete work in x days)
Now we need to find out the value of x from following
(1/20+1/15)*6 + (1/20+1/x)*4 = 1
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