c=(byte)(a+b);

solve this is my problem byte a=40,byte b=50 both add value is 90 this is with in range of byte... byte range is -128to 127....
why this pgm gives error like type mismatch....

package javapgms;

public class byte1 {

public static void main(String args[])
{
byte a=40,b=50;
byte c=a+b;

System.out.println(c);
}

}
note : dont use int k...
a,b,c are in byte range... mind it..

Question Posted / siva

2 Answers
6287 Views
I also Faced
E-Mail Answers

Answer Posted / siva

c=(byte)(a+b);

Is This Answer Correct ?

0 Yes

0 No

Post New Answer View All Answers

Please Help Members By Posting Answers For Below Questions

Does java support Operator Overloading?

1041

Can we pass a primitive type by reference in java? How

933

What is the difference between post and put?

1066

What is role of void keyword in declaring functions?

1050

What do you mean by buffering?

1045

Is java 9 released?

1006

What does || mean in vectors?

931

What is a blocking method in Java?

1240

What do you meant by active and passive objects?

1084

How do you declare a string variable?

1017

What is Mutex (Mutual Exclusion Object) ?

1152

How is treeset implemented in java?

1027

What is the difference amongst jvm spec, jvm implementation, jvm runtime ?

968

Does constructor be static?

1035

What are functions in java?

950