a)If column dimensions are 250*400mm , what will be
cutting length for 8mm stirrups and how to calculate it? b)
If beam dimensions are 200*400mm , beam coveris 25mm , slab
cover is 20mm , what will be the cutting length for
stirrups? c)Column dimensions are 250*400mm , reinf. is
12nos. bar of 16mm dia , stirrups provided are two legged,
what will be the length of each ring?
Regards
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Answer Posted / hi123
Given Data : Column size = 250x400 Clear Cover = 40 mm Dia of Stirrup = 8 mm
Ans: To calculate cutting length first we determine the lengths A and B
So A = 250-2x40+2x(half dia of stirrup) = 250-80+2x4 = 178
B = 400-2x40+2x(half dia of stirrup) = 400-80+2x4 = 328
Deductions : For bents up we must deduct the values that for
45 degree bent = 1d
90 degree bent = 2d
135 degree bent = 3d where d = dia of stirrup
here in our case for the hooks there are 2 bends of 135 degree each
for the stirrup there are 3 bends of each 90 degree
so deductions = 2x3xd + 3x2xd = 2x3x8 + 3x2x8
Addings up ---> we have to add up hook lengths here in our case each hook length = 12 d so for 2 hooks the hook length = 12d+12d = 24d
So now the actual cutting length = 2(A+B)-2x3x8-3x2x8+24x8
= 2(178+328)-2x3x8-3x2x8+24x8
= 1012-48-48+192 = 1108 = 1.108 m.
Note : It is only correct answer I assure to you all which will be the elsewhere worthwhile in whole india you can check up
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