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Radius of sphere is increased by 50%. By how much percentage
is surface area is increased?
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Answer Posted / harsh goel
let the edge of cube be=x
the edge increased by 50%
=x+50÷100
=x(1+1/2)
=3x/2
orignal surface area=6x^2
new surface area of a cube=6(3x/2)^2
=6×9x^2/4
=27x^2/2
increased in area of cube=27x^2-12x^2/2
=15x^2/2
the percentage increased=increase in area/orignal area ×100
=15×100/2×6x^2
=1500/12x^2
=125%
| Is This Answer Correct ? | 13 Yes | 5 No |
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