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Radius of sphere is increased by 50%. By how much percentage
is surface area is increased?
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Answer Posted / satyam
1st sphere=x and 2nd sphere=y then
x=4(22/7)×100 50=4(22/7)150
y=4(22/7)×100=4(22/7)100
area={(x-y/x))r2
={4(22/7)150-4(22/7)100/4(22/7)100}r2
={4(22/7)50/4(22/7)100}r2
={50/100}r2
=.5×r2 ;0.5×0.5=0.25 = 100 25= 125%
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