find the remainder when 2222^(5555)+5555^(2222)is divided
by 7
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Answer Posted / prakash kumar ojha
3^5555 +4^2222
=3^5*1111 +4^2*1111
=(3^5)^1111 +(4^2)^1111
=243^1111 +16^1111
Which is divisible by 243+16=259
[x^n + y^n always divisible by x+y if n is odd]
But 259 is divisible by 7
Therefore 3^5555 + 4^2222 is divisible by 7
| Is This Answer Correct ? | 18 Yes | 3 No |
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