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What is the four-digit number in which the first digit is
1/3 of the second, the third is the sum of the first and
second, and the last is three times the second?
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Answer Posted / nessa
first=f,second=s,third=T,Last=L
f=s/3
T=f+s
L=3s
since s is divisible by 3,so s can be 3,6,9
Taking s=3
f=1
T=3+1=4
L=3*3=9
so answer is 1349
| Is This Answer Correct ? | 5 Yes | 1 No |
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