Answer Posted / kang chuen tat (malaysia - pen

Rearranging the equation (1/y)(dy) = [ x / (Z 1) ] (dx). Use the additional equation u = Z 1, du = 2x dx, 0.5 du = x dx. Then the equation becomes (1/y)(dy) = (0.5)(1/u) du. Integrating both sides of the equation gives ln |y| = (0.5) ln |Z 1| c where Z = square of x. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS 61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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